Solve if you can

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Claude
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Solve if you can

Post by Claude »

Isn't that the idea of puzzles ?

Anyway, here you go:
mathprob.jpeg
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Cheers, Claude.

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HansV
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Re: Solve if you can

Post by HansV »

Spoiler
98
Regards,
Hans

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Argus
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Re: Solve if you can

Post by Argus »

Spoiler
99
Byelingual    When you speak two languages but start losing vocabulary in both of them.

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Claude
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Re: Solve if you can

Post by Claude »

I agree with Argus.
Cheers, Claude.

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HansV
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Re: Solve if you can

Post by HansV »

I don't :grin:
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Hans

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Claude
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Re: Solve if you can

Post by Claude »

HansV wrote:I don't :grin:
Made me think, me neither, me agree with Hans now :blush:
Cheers, Claude.

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Rudi
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Re: Solve if you can

Post by Rudi »

Spoiler
1>3>5>7>9
I get 99?

Argus, shall we band together as the odd ones out? :grin:
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Rudi

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HansV
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Re: Solve if you can

Post by HansV »

Argus and Rudi's reasoning would have been correct if the numbers in the last row were 11 and 10.
Spoiler
The answer would then have been 11*10+9 = 119
But the sequence in the first column is 3 > 5 > 7 > 9 > 10, not 11...
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Hans

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StuartR
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Re: Solve if you can

Post by StuartR »

I agree with Hans,
Spoiler
98
StuartR


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HansV
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Re: Solve if you can

Post by HansV »

This is my reasoning:
Spoiler
3 x 2 + 1 = 7
5 x 4 + 3 = 23
7 x 6 + 5 = 47
9 x 8 + 7 = 79
So
10 x 9 + 8 = 98
and
11 x 10 + 9 = 119
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Hans

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Rudi
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Re: Solve if you can

Post by Rudi »

Your reasoning seems reasonable.

Argh! Who are we kidding....it sounds quite sound. :thumbup:
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Rudi

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Argus
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Re: Solve if you can

Post by Argus »

StuartR wrote:I agree with Hans,
Spoiler
98
Me too. That's what happens being in between coffee, I guess. :grin: In this case it was simple, and rather sneaky.

Rudi, I'm not odd anymore, well, at least not in this thread. :grin:
Byelingual    When you speak two languages but start losing vocabulary in both of them.

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HansV
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Re: Solve if you can

Post by HansV »

You're even now?
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Hans

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Argus
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Re: Solve if you can

Post by Argus »

As even as one person can be.
Byelingual    When you speak two languages but start losing vocabulary in both of them.

Becks
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Re: Solve if you can

Post by Becks »

I would have thought that the simplest explanation was
n*n - 2 where n is the first number
There is no additional information in the second number, but if you had to use it, then
n*n - 2*(n - m) where m is the second number

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StuartR
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Re: Solve if you can

Post by StuartR »

Becks wrote:n*n - 2 where n is the first number
:clapping:
StuartR


mirfield
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Re: Solve if you can

Post by mirfield »

Becks wrote:I would have thought that the simplest explanation was
n*n - 2 where n is the first number
There is no additional information in the second number, but if you had to use it, then
n*n - 2*(n - m) where m is the second number
I also got 98, but I was using n*m+m-1

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AlanMiller
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Re: Solve if you can

Post by AlanMiller »

Or n2 + 2n - 1 if n is the second number. But who's counting.

Alan