## Solve if you can

Claude
cheese lizard
Posts: 6241
Joined: 16 Jan 2010, 00:14
Location: Sydney Australia

### Solve if you can

Isn't that the idea of puzzles ?

Anyway, here you go:
mathprob.jpeg
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Cheers, Claude.

HansV
Posts: 75263
Joined: 16 Jan 2010, 00:14
Status: Microsoft MVP
Location: Wageningen, The Netherlands

### Re: Solve if you can

Spoiler
98
Regards,
Hans

Argus
GoldLounger
Posts: 3081
Joined: 24 Jan 2010, 19:07

### Re: Solve if you can

Spoiler
99
Byelingual    When you speak two languages but start losing vocabulary in both of them.

Claude
cheese lizard
Posts: 6241
Joined: 16 Jan 2010, 00:14
Location: Sydney Australia

### Re: Solve if you can

I agree with Argus.
Cheers, Claude.

HansV
Posts: 75263
Joined: 16 Jan 2010, 00:14
Status: Microsoft MVP
Location: Wageningen, The Netherlands

### Re: Solve if you can

I don't
Regards,
Hans

Claude
cheese lizard
Posts: 6241
Joined: 16 Jan 2010, 00:14
Location: Sydney Australia

### Re: Solve if you can

HansV wrote:I don't
Made me think, me neither, me agree with Hans now
Cheers, Claude.

Rudi
gamma jay
Posts: 25432
Joined: 17 Mar 2010, 17:33
Location: Cape Town

### Re: Solve if you can

Spoiler
1>3>5>7>9
I get 99?

Argus, shall we band together as the odd ones out?
Regards,
Rudi

If your absence does not affect them, your presence didn't matter.

HansV
Posts: 75263
Joined: 16 Jan 2010, 00:14
Status: Microsoft MVP
Location: Wageningen, The Netherlands

### Re: Solve if you can

Argus and Rudi's reasoning would have been correct if the numbers in the last row were 11 and 10.
Spoiler
The answer would then have been 11*10+9 = 119
But the sequence in the first column is 3 > 5 > 7 > 9 > 10, not 11...
Regards,
Hans

StuartR
Posts: 12109
Joined: 16 Jan 2010, 15:49
Location: London, Europe

### Re: Solve if you can

I agree with Hans,
Spoiler
98
StuartR

HansV
Posts: 75263
Joined: 16 Jan 2010, 00:14
Status: Microsoft MVP
Location: Wageningen, The Netherlands

### Re: Solve if you can

This is my reasoning:
Spoiler
3 x 2 + 1 = 7
5 x 4 + 3 = 23
7 x 6 + 5 = 47
9 x 8 + 7 = 79
So
10 x 9 + 8 = 98
and
11 x 10 + 9 = 119
Regards,
Hans

Rudi
gamma jay
Posts: 25432
Joined: 17 Mar 2010, 17:33
Location: Cape Town

### Re: Solve if you can

Your reasoning seems reasonable.

Argh! Who are we kidding....it sounds quite sound.
Regards,
Rudi

If your absence does not affect them, your presence didn't matter.

Argus
GoldLounger
Posts: 3081
Joined: 24 Jan 2010, 19:07

### Re: Solve if you can

StuartR wrote:I agree with Hans,
Spoiler
98
Me too. That's what happens being in between coffee, I guess. In this case it was simple, and rather sneaky.

Rudi, I'm not odd anymore, well, at least not in this thread.
Byelingual    When you speak two languages but start losing vocabulary in both of them.

HansV
Posts: 75263
Joined: 16 Jan 2010, 00:14
Status: Microsoft MVP
Location: Wageningen, The Netherlands

### Re: Solve if you can

You're even now?
Regards,
Hans

Argus
GoldLounger
Posts: 3081
Joined: 24 Jan 2010, 19:07

### Re: Solve if you can

As even as one person can be.
Byelingual    When you speak two languages but start losing vocabulary in both of them.

Becks
2StarLounger
Posts: 195
Joined: 31 Mar 2011, 03:41
Location: Perth, Western Australia

### Re: Solve if you can

I would have thought that the simplest explanation was
n*n - 2 where n is the first number
There is no additional information in the second number, but if you had to use it, then
n*n - 2*(n - m) where m is the second number

StuartR
Posts: 12109
Joined: 16 Jan 2010, 15:49
Location: London, Europe

### Re: Solve if you can

Becks wrote:n*n - 2 where n is the first number
StuartR

mirfield
Lounger
Posts: 27
Joined: 04 Jun 2013, 08:32
Location: North Yorkshire, UK

### Re: Solve if you can

Becks wrote:I would have thought that the simplest explanation was
n*n - 2 where n is the first number
There is no additional information in the second number, but if you had to use it, then
n*n - 2*(n - m) where m is the second number
I also got 98, but I was using n*m+m-1

AlanMiller
BronzeLounger
Posts: 1545
Joined: 26 Jan 2010, 11:36
Location: Melbourne, Australia

### Re: Solve if you can

Or n2 + 2n - 1 if n is the second number. But who's counting.

Alan